display: block; Otherwise, there is no point in getting a critical area. Save when you order the Complete Fire Tech Reference Library. Detailed review of NFPA 12 and 70 2011, NFPA 72 2013 and NFPA 2001 2012 (per level of study). Dear Guests, if the above information is a matter of sight, you can help to reach the most correct solution by commenting. width:auto; height:auto; a) Pressure loss due to friction text-shadow:0px 0px 0px #d6d6c6; padding:5px; My issue with geometry was that I knew how to plug in the numbers, but I did not know what the numbers really meant. width:470px; padding:5px; The numerous NFPA 70 2014, NFPA 72 2016 and IBC 2015 references, charts and graphs make the text easy to read and follow. margin:0px; -webkit-border-radius:20px; a) Line 7 Pressure loss due to friction margin:0px; background-color: #ffffff; This book is a fundamental reference covering Fire Alarm Systems concepts. } gtag('js', new Date()); The detailed explanations and outlines are perfect for those preparing for the NICET Inspection & Testing of Water-Based Systems exams. To build on this concept and further prepare for your NICET Level I exam, check out our resources! Flow Pressure Qm = Km P 60 = 80 P P = 0,5625 bar, 1 line d) Static Height 27 m Ps = 0.098 * 27 = 1.7640 Pm = 6.05 [458,3^ 1,85 / (120^ 1,85 53,4,4,87)] 10^ 5 = 0.0289 bar width:780px; Detailed review of NFPA 13 2016, NFPA 16 2015, NFPA 20 2016, NFPA 25 2017, NFPA 72 2016, NFPA 291 2016. Water-Based Systems Layout Basic, Intermediate, General Plans & Hydraulics Reference Texts. Fire Alarm Systems Advanced Reference Text. While I was good at math in high school, I was taught a harsh lesson during my first geometry test: I had memorized all the right equations, but I had no idea how to solve the actual problems. The following illustration shows the critical area. Straight Pipe: 2.1 m The Km value will vary depending on the value of your sprinkle orifice. width:280px; height:auto; The Fire Alarm Systems Reference Text covers: Fire Alarm Systems Basic, Intermediate & Advanced Texts, Inspection & Testing of Fire Alarms Text, Inspection & Testing of Water-Based Systems Basic & Intermediate Texts, Special Hazards Text, and Water-Based Systems Layout Basic, Intermediate, General Plans & Hydraulics Reference Texts. 6 line(for 2 to 21/2 switch) You need JavaScript enabled to view it. #access { Effective tips, hints and test strategies to help lead you to exam day success. When faced with more advanced concepts that will show up on higher level NICET exams, knowing the basics of the problem becomes very important. background:#fff; width:900px; We now add this flow to the flow in the seconded pipe [120]-[110] to find the total flow in the third pipe [110]-[100] which will give us the flow of 244.20 L/min. *Fire Tech Productions recommends their online NICET prep courses for the best preparation possible. Total = 3 + 1.9 = 4.90 In each of the points in the critical line in the 2-line table direction and in the lines outside the critical area, only the number of points with the diameter change is given. color: #ffffff; width:100%; -webkit-border-radius:10px; /* Safari and Chrome */ We now need to add the pressure loss in the pipe to the start pressure at the sprinkler head at node [130] which was 1.19 bar to find to pressure at node [120] and at the seconded sprinkler head at node [120] this gives us 1.194 + 0.086 = 1.28 bar. -moz-border-radius:10px; /* Firefox */ Pipe Type: Black Steel (Wet and Tough System) Pm = 6.05 [60^ 1,85 / (120^ 1,85 27,2 ^ 4,87)] 10 ^ 5 = 0,0173 bar Total = 3.8 + 2.4 = 6.2 Over 2 hours of recorded content covering 12 key subjects. Sample Sprink Column Schematic:Sample Sprink Calculation Autocad Download. Developing an understanding for the topics that show up on the NICET exams will not only help you pass the test, but it will make you a better worker in this life safety industry. Detailed review of NFPA 72 2013 (per level of study). behavior: url(/css/border-radius.htc); The following NICET approved Standards and Fire Tabs in addition to your Online Course purchase: Level I & II: NFPA 70 2011, NFPA 72 2013 and IBC 2012, Level III: NFPA 70 2011, NFPA 72 2013, IBC 2012 and NFPA 101 2012. -webkit-border-radius:10px; /* Safari and Chrome */ Prior to joining Fire Tech Productions, Tom Frericks Jr. owned Copp Integrated Systems in Dayton, OH. This mindset of understanding the particulars of an industry concept do not just apply to mathematical equations, but everything in the fire protection industry. If it were not for the same, we would have to recalculate these merging lines. Hydraulic calculations become much more digestible when we know what is really going on behind the equation. window.dataLayer = window.dataLayer || []; } b) Equivalent Length for 7 line resistance values Pm = 6.05 x [Qm ^ 1,85 / (C ^ 1,85 dm ^ 4,87)] 10 ^ 5 4- Wewill use it in calculations Identify Equivalent Length Values, Pipe Diameters, Coefficient of C, and Correction table and formulas to use. -moz-border-radius:20px; Reference Text. This text contains 339 pages. .rounded-corners { For this reason, it is not right to choose the main line diameter especially by looking at the table, it is necessary to determine the correct diameter by hydraulic calculation. Because of the spring in the system, a total of 458 + 100 + 400 = 958 l / min is obtained by adding 100 l / min for the fire cabin and 400 l / min for the hydrant from the Additional Water Requirements for Fire Cabinets and Hydrant System min For a flow rate of 57,5 m / h, your pump flow should be approx. margin:5px; -moz-border-radius:10px; /* Firefox */ Total = 2.1 + 0.77 = 2.87 height:auto; There are three variables that are used for this equation, so lets break those down. The Water-Based Systems Layout Basic Reference Text covers: Water-Based Systems Layout Intermediate Reference Text. text-shadow:0px 0px 0px #d6d6c6; Detailed review of NFPA 25 2014 (per level of study). 10-15 minute videos accompany each individual lesson. This book is a fundamental reference covering Fire Alarm Systems concepts. Design Density: 5 lt / dk.m (selected from the Design Density table in Annex-8 / B Sprinkler System) We will for this example use simple three sprinklers and three pipes which would of course be part of a much larger fire sprinkler system. Total = 27 + 21.6 + 11.1 = 59.70 If you look carefully at first the NFPA table line in the inner line of the line was done and the main line was the hydraulic calculations by taking my experience as the final 3 . Required fields are marked *. In general, the process is to select the pump at 58 m / h 80 ms, taking the highest pressure loss to stay on the safe side. text-decoration: none; *Our courses are guaranteed for exam success when students who possess the level of experience (corresponding with the certification requirements) have studied each lesson & taken and passed each quiz/exam within each level of training, up to and including their exam level. The next step is to find the flow from the seconded sprinkler head at node [120] to do this we will use the K-Factor formula. Coupling this text with our Fire Alarm Systems Level I Online Course is a perfect study package for those preparing for the NICET Fire Alarm Systems Level I exam. text-shadow: 0; } The Water-Based Systems Layout Intermediate Reference Text covers: Water-Based Systems Layout Advanced General Plans Reference Text. box-shadow: none !important; margin:5px; #139 Top Differences between Conventional and Addressable Fire Alarm Systems, NICET Exam Practice Session Calendar (PDF). d) Static Height 3 m Ps = 0.098 * 3 = 0.294 Four GREAT Reference Texts, One Low Price! background:#fff; f) Psychosis = 0.0376 6.2 = 0.2332 bar Not knowing the math basics needed for hydraulic calculations is intimidating and lack of confidence on top of that can keep you from advancing to the next level in your career. The numerous NFPA 70 2014, NFPA 72 2016, NFPA 101 2015 and IBC 2015 references, charts and graphs make the text easy to read and follow. 90 days (single level purchase) self-paced study online access. .entry-content ul.disc > li { list-style: disc; } a) 4 to 1 Qbalans = Qd x ( Pb / Pk) = 62,59 (1,2032 / 0,6122) = 87,75 l / min Many individuals who take the NICET exams encounter a similar issue when it comes to the concept of hydraulic calculations. margin:5px; -moz-border-radius:10px; /* Firefox */ This text contains 335 pages. The last step is to find the pressure loss in the third pipe [110]-[100] and again we will use the Hazen-Williams pressure loss formula given is formula 4 above. -webkit-border-radius:10px; /* Safari and Chrome */ This article will demonstrate some of the basics for carrying out fire sprinkler calculations by the long-hand method with just the aid of a scientific calculator or our ownhydraulic calculator - Hcal2 which you can freely download from our website. b)Minimum Pressure Qm = Km P In this example, we have kept it very simple and used the same sprinkler head for all three sprinklers but this may not always be the case so again it may be useful to summarise the information in a table such as this: The first step is to calculate the minimum flow which will be required at the most remote sprinkler which in this case is at node [130], this is a two-step process as will need to calculate the minimum flow required to satisfy the 7.50 mm/min design density and then find the flow rate from the sprinkler given the sprinklers minimum pressure requirement, whichever is the greater flow will become our initial flow from the first sprinkler at node [130]. c) Qbransman = Qbalans + Qbalans + Qbars = 87,75 + 87,75 + 282,8 = 458,3 lt / min (adsbygoogle = window.adsbygoogle || []).push({}); The purpose of the sprinkler system;to provide early response to the fire and to discharge the amount of water on the design area within a certain period of time to control and extinguish the fire. e) Equivalent Length for 5 line resistance values We know that the flow rate from the sprinkler at node [130] is 76.50 L/min and this will be the flow rate in the first pipe between nodes [130]-[120]. The Special Hazards Basic Reference Text covers: Fire Alarm Systems Basic Reference Text. If you pay attention after you have done the balancing process, you will notice that there is no new flow and balance calculation from now on the critical hattan in this project. Flat Pipe: 1,0 m Water-Based Systems Layout Hydraulics Reference Text, Inspection & Testing of Water-Based Systems Basic & Intermediate Reference Texts. e) Branch Debt = Qm = Km P = 80 0,6122 = 62,59 l / min, 2 lines We now need to find the flow from the sprinkler at node [110] we do this by using the k-factor given in equation 5 as we now know the pressure at node [110] is 1.597 bar, this gives 70 x 1.5970.5 = 88.50 L/min from the sprinkler head at node [110]. Loaded with NFPA references, these texts will become a valuable asset both in the field and office. e) Psychosis = 0,0675 5,3 = 0,3578 bar b) 4 to 2 Qbalans = Qd (Pb / Pk) = 61,61 (1,2032 / 0,5932) = 87,75 l / min The question is asking for the K-Factor, so we know to use: Plug everything in, and our formula will look like: Building Design Impacting Sprinkler System Layout, Construction Impacting Sprinkler System Layout, Building Features Impacting Sprinkler System Layout, Inspection and Testing of Sprinkler Systems. This well-written text will become the cornerstone of your Fire Protection Library! Pm = 6.05 x [Qm ^ 1,85 / (C ^ 1,85 dm ^ 4,87)] 10 ^ 5 margin:5px; You can download the file as dwg. Straight Pipe: 27 m This well-written text will become the cornerstone of your Fire Protection Library! height:auto; padding:5px; a) Line 6 Pressure loss due to friction } } However, the correct pump selection must be made by looking at the pump curve. (Pncekit, total pressure of the previous line 0.5625 + 0.0497 = 0.6122 bar). Repeat steps 4 to 6 until you do not have any more sprinklers or pipes. We know that learning higher math concepts can make you feel a little queasy. .box { #access > .menu > ul > li > a > span:hover { e) Ptoplam = P5 + P6 line + Ps = 1,8220 + 0.0398 +0,294 = 2,1558 bar, Line 7(for 21/2 to 3 ) Sample Sprink Calculation Autocad Download, Fire Installation Pipe Diameters, NFPA 13-1999, Pipe Tray Method, Black Steel Pipe (Dry and pre-reacting system). OC305985, Hydraulic calculations for fire protection engineers. padding:5px; The eight chapter Water-Based Systems Layout Advanced Hydraulics Reference text is an invaluable reference for Water-Based Systems Layout professionals. } #main { Basic Reference Text. 1 pcs teat: table for the diameter of 11/2 2,4 In this section, 4 lines connecting to this point line 1 and 2 line are combined with the same line. (Because 1 and 2 are the same, you can not give this number different numbers if you do not want to print, but you do not have to number them extra if the pressures are the same. Two GREAT Reference Texts, One Low Price! Videos were designed to supplement the Water-Based Layout Level I Online Course. The Inspection & Testing of Fire Alarm Systems Reference Text covers: Water-Based Systems Layout Basic Reference Text. Pm = 6.05 [125,2^ 1,85 / (120^ 1,85 27,2 ^ 4,87)] 10^5 = 0,0675 bar height:auto; 1 te: table for 1 diameter 1,5 (You can unsubscribe anytime), Inspection & Testing of Water-Based Systems 2 butterfly valves, 1 check valve 3 diameter for table 11,1 1-First of all, inaccordancewith theregulation onthefire protection ofthe buildings, criteria for the buildings hazard class and sprinkle design are determined. The fifteen chapter Inspection & Testing of Water-Based Systems Intermediate Reference text is an invaluable reference for Water-Based Systems professionals. If there is only a change in diameter, we will calculate the pressure losses in these areas. This text contains 237 pages. -webkit-border-radius:10px; /* Safari and Chrome */ Add the head pressure to the pressure loss in step 4 to determine the pressure at the next sprinkler. 2-After designing in the project, use diameters according to the number of sprinkles using the following NFPA table for diameter. This fourteen chapter Inspection & Testing of Fire Alarm Systems Reference text is an invaluable reference for Fire Alarm Systems Technicians and Professionals. This fourteen chapter Fire Alarm Systems Intermediate Reference text is an invaluable reference for Fire Alarm Systems Technicians and Professionals. border-radius: 10px; background:#222222; padding:0px; height:auto; This book is a fundamental reference covering Inspection & Testing of Fire Alarm Systems concepts. Copyright 2022 | Tesisat.org Tm haklar sakldr. The diameter of the fixed pipe installation that supplies water to the sprinkler system should be determined according to the hydraulic calculations to be made. $ave when you order the combo package. behavior: url(/css/border-radius.htc); b) 3 to 2 Qbalans = Qd x ( Pb / Pk) = 61,61 (0,97 / 0,5932) = 78,79 l / min Total = 3,8 + 1,5 = 5,3 These basic procedures can also be used for calculating many other types of systems such as fire hydrants, hose reels or the discharge from a water cannon or monitor we can also use the same principle for almost all other water-based fire protection systems if we have a k-factor for the output device (fire sprinkler, water mist nozzle and so on). background:#fff; The following NICET approved Standards in addition to your Online Course: The following NICET approved tabbed Standards: To purchase individual standards, click here. .widget_sow-tabs { Four hours of supplemental content expanding on course lesson material. Hydraulic calculations are used to determine the pressure and output of water (flow) for a given sprinkler system. 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